SongKong Jaikoz

SongKong and Jaikoz Music Tagger Community Forum

How to avoid discno on single disc releases

#1

Hi,

I recently purchased Songkong Pro and am getting it configured.

First question: How do I stop it writing disc-number information to single disc releases? I do want the discno on multidisc releases ? both in the metadata and the folder name ? but not on single discs …

Thanks
Ian

#2

It shoudn’t write to metadata
It shoudn’t write to folder structure unless multi disc

If that is what you are seeing please run Create Support Files so I can look at your options and your results.

#3

Support files uploaded …

Cheers
Ian

#4

Ah you have found a bug/regression.
When matching to MusicBrainz it is applying the value of the Format:Multi Disc Releases to all releases, it should only be doing it for releases with more than one disc !

I have raised an issue

https://jthink.atlassian.net/browse/SONGKONG-1635

Easy to fix, but I wont be able to do a release this week, workaround would for now to set that option to Never add Disc Info to release title

Sorry about that.

#5

Thanks. I’m glad it’s a bug - in the sense that I haven’t completely misunderstood how the program is supposed to work … :wink:

No hurry with the fix. I can wait.

One more question with relation to this feature: is it possible to specify how (and where) the disc number gets written? I would prefer (CD01) rather than (disc 1) if possible. I tried to add it to the file renaming mask but then the discno. appeared twice!

Cheers
Ian

#6

You cannot specify when adding to a release title.
But you can specify when adding to rename mask using appropriate Javascript, so you could either not add to album name and then just add to filename using isMultiDisc() function as a condition, or if you want it in release name as well then you would have to filter out from releaseName when using as part of the filename mask.

#7

OK, thanks. How would I go about filtering it out of the rename mask? I’m not all that fluent in javascript.

#8

I don’t know exact syntax but use a regular expression with replace I guess , but the great thing about it being Javascript is you can consult any book or Javascript forum to find an answer.